remove_Inf()
remove rows/columns that contain infinite values.replace_Inf
replaces infinite values values.
Usage
remove_Inf(x, ...)
replace_Inf(x, ...)
# S4 method for ANY
remove_Inf(x, margin = 1, all = FALSE)
# S4 method for matrix
replace_Inf(x, value = 0)
# S4 method for data.frame
replace_Inf(x, value = 0)
Arguments
- x
An R object (should be a
matrix
or adata.frame
).- ...
Currently not used.
- margin
A length-one
numeric
vector giving the subscripts which the function will be applied over (1
indicates rows,2
indicates columns).- all
A
logical
scalar. IfTRUE
, only the rows/columns whose values all meet the condition defined byf
are considered. IfFALSE
(the default), only rows/columns where at least one value validates the condition defined byf
are considered.- value
A possible replacement value.
Examples
## Create a data matrix
X <- matrix(sample(1:10, 25, TRUE), nrow = 5, ncol = 5)
## Add Inf
k <- sample(1:25, 3, FALSE)
X[k] <- Inf
X
#> [,1] [,2] [,3] [,4] [,5]
#> [1,] 1 3 Inf 4 Inf
#> [2,] 8 5 7 9 1
#> [3,] 6 2 5 6 8
#> [4,] 7 7 5 Inf 5
#> [5,] 7 8 4 1 3
## Remove rows with Inf
remove_Inf(X, margin = 1)
#> [,1] [,2] [,3] [,4] [,5]
#> [1,] 8 5 7 9 1
#> [2,] 6 2 5 6 8
#> [3,] 7 8 4 1 3
## Replace Inf with zeros
replace_Inf(X, value = 0)
#> [,1] [,2] [,3] [,4] [,5]
#> [1,] 1 3 0 4 0
#> [2,] 8 5 7 9 1
#> [3,] 6 2 5 6 8
#> [4,] 7 7 5 0 5
#> [5,] 7 8 4 1 3